Math, asked by saniataj95gmailcom, 1 year ago

population of a village increased by 15% from 2005 to 2006 and by 50% from 2006 to 2007. if the population of the village was 440 in 2005,what was it's population in 2007.

Answers

Answered by qudsiya9950

population of town in 2005 = 440

population increases every year = 50%

population of town in 2006 = 50% of 440

=> 50/100×440

=> 5×44

=> 220

New number = 440+220 = 660

Population of town in 2007 = 50% of 660

=> 50/100×660

=> 5 × 66

=> 330

new number = 660+330 = 990

ANS :- Population of town in 2007 = 990

saniataj95gmailcom: answer options is 751,781,759,765,753

saniataj95gmailcom: A started a business with an investment of rs 24000.after 2 months B joins with rs 16000 and after another 2 months C joins with RS 20,000.at the end of 8th month from start of the business, if A withdraws RS. 4000, B withdraws RS.2000 and C invests RS.4000. what is the respective ratio in which the profit should be distributed among A, B ,C at the end of the year.

qudsiya9950: sorry

Answered by apurvajain30

15%of 440

15/100 of 440

=66

population in 2006=440+66=506

50%of 506= 253

population in 2007= 253+440=693

saniataj95gmailcom: tq

apurvajain30: don't know

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population of a village increased by 15% from 2005 to 2006 and by 50% from 2006 to 2007. if the population of the village was 440 in 2005,what was it's population in 2007.​

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ANS :- Population of town in 2007 = 990

population of a village increased by 15% from 2005 to 2006 and by 50% from 2006 to 2007. if the population of the village was 440 in 2005,what was it's population in 2007.