Question

Population of town 3 years ago was 60000 . If annual increase in three successive year is at rate 4% , 5% , 6% .Find the present population. ​

Answer 1

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Population of the town =60,000.

Rate of increase for the first year (p)=5%

Rate of increase for the second year (q)=4%

Rate of increase for the third year (r)=3%

Time =3 years

Now, 

Present population =P×(1+100p)×(1+100q)×(1+100r)=60000×(1+1004)×(1+1005)×(1+1006)=60000×100104×100105×100106=6×21×26×21.2=69451.2

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Answer 2

answer in picture

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