. ∠POQ=64 , Arm PO is produced up to point R and OS is the bisector of
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Angle POQ=64. arm PO is produced upto point R and OS is the bisector of Angle QOR. Find the measure of Angle POS.. ∠ POQ = 46 ° Given Let ∠ QOS = x ∠ QOS = ∠ ROS
It is given that line YQ bisects ∠PYZ.
Hence,
∠QYP = ∠ZYQ
PX is straight line
sum of angle in linear pair always equal to 180°
∠XYZ + ∠ZYQ + ∠QYP = 180°
Give that so plug the value we get ∠ XYZ = 64°
And ∠QYP = ∠ZYQ
And ∠QYP = ∠ZYQ
∠ 64° + 2∠QYP = 180°
∠2∠QYP = 180° − 64° = 116°
Divide by 2 we get
∠QYP = 58°
Also, ∠ZYQ = ∠QYP = 58°
Using angle of reflection
∠QYP = 360° − 58° = 302°
∠XYQ = ∠XYZ + ∠ZYQ
= 64° + 58°
= 122°
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