Question

por 2) Two capacitors each of 4uF are connected in series and a third capacitor of 4uF is connected in parallel with the combination then the equivalent capacitance of the combination is ​

Answer 1

Answer:

6uF

Explanation:

we have three capacitors,

C1=4uF

C2=4uF

C3=4uF

Now acc to question,

C1 and C2 are connected in series,

so Total capacitance of combination -

(1/C12)= ( (1/C1)+(1/C2) )

=(1/4)+(1/4) = (2/4) =(1/2)

C12=2

Now C3 is connected in parallel with combination C12 .

so total equivalence capacitance of combination is:

C123= C12+C3

C123= 4 + 2 = 6

Hence equivalent capacitance is 6uF.