Question

POR to a triangle night angled at p. if PQ = 10 cm
PR - 24 cm
find ceR​

Answer 1

• Correct Question

PQR is a triangle right angled at P. If PQ = 10 cm

PR = 24 cm

Find QR.

• Given

• PQR is a right angled triangle
• PQ = 10 cm
• PR = 24 cm

• To find

• Length of QR

• Solution

By pythagoras theorem

• H² = P² + B²

where,

• H = Hypotenuse (Longest side)
• P = Perpendicular
• B = Base

Substituting the given values,

⇒ QR² = PQ² + PR²

⇒ QR² = 10² + 24²

⇒ QR² = 100 + 576

⇒ QR² = 676

⇒ QR = ± √676 Reject - ve

⇒ QR = 26 cm

• QR = 26 cm

Figure -

$\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(.3,2.5){\large\bf 10~cm}\put(2.8,.3){\large\bf 24~cm}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf Q}\put(.8,.3){\large\bf P}\put(5.8,.3){\large\bf R}\end{picture}$