Question

PORS is a parallelogram. QM is the
perpendicular from Q to SR and QNM
is the perpendicular from Q to PS.
If SR = 12 cm and QM = 6 cm, find
the area of a parallelogram PQRS.​

Answer 1

Answer:

Given: SR=12cm, QM=7.6cm, PS=8cm.

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm 2

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm 2 .

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm 2 .Area of parallelogram=base×height

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm 2 .Area of parallelogram=base×height⇒91.2=8×QN

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm 2 .Area of parallelogram=base×height⇒91.2=8×QN⇒QN=

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm 2 .Area of parallelogram=base×height⇒91.2=8×QN⇒QN= 8

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm 2 .Area of parallelogram=base×height⇒91.2=8×QN⇒QN= 891.2

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm 2 .Area of parallelogram=base×height⇒91.2=8×QN⇒QN= 891.2

Given: SR=12cm, QM=7.6cm, PS=8cm.Area of parallelogram=base×height=12×7.6=91.2cm 2 .Area of parallelogram=base×height⇒91.2=8×QN⇒QN= 891.2 =11.4cm.

HOPE IT'LL HELP :)