Question

PORS is a square and PQT is an equilateral triangle outside the square, then

Answer 1

Answer:

Step-by-step explanation:

Because PQRS is a square

∠PSR=∠QRS=90

Now In △SRT ( solve PQT like this)

∠TSR=∠TRS=60

∠PSR+∠TSR=∠QRS+∠TRS

∠TSP=∠TRQ

Now in △TSP and △TRQ

TS=TR

∠TSP=∠TRQ

PS=QR

Therefore , △TSP≡△TRQ

So PT=QT

(ii) Now in △TQR,

TR=QR(RQ=SR=TR)

∠TQR=∠QTR

∠TQR+∠QTR+∠TRQ=180

∠TQR+∠QTR+∠TRS+∠SRQ=180

2(∠TQR)+60+90=180 (∠TQR=∠QTR)

2(∠TQR)=30

∠TQR=15