PORVE ROOT 2 IS RATIONAL
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Answer:
√2is a irrational number but not an rational
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Step-by-step explanation:
Let us assume√2 is rational
If it is rational, then there must exist two integers r and s(s ≠0) such that √2 = r/s.
If r and s have a common factor other that 1.
If we get √2 = a/b, where a and b are co-primes. So, b√2 = a.
Squaring on both sides, we get 2b^2 = a^2.
Therefore, 2 divides a^2.
(by theorem) 2divides a.
We can write a =2c for some integer c.
We get 2b^2 = 4c^2, that is b^2 = 2c^2
=> 2 divides b^2
=> 2 divides b
a and b have 2 has a common factor.
But contradicts that a and b are co-prime.
Our assumption that √2 is rational. So, Our assumption is false.
Therefore, that √2 is irrational.
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