Question

POS form of AB+AC+BC​

Answer 1

Answer:

Y (A, B, C) = AB + BC + CA, this expression is a SOP expression, since we notice the Boolean function has three literals A, B and C, so each term of the Boolean expression must contain all the three literals to convert it into canonical SOP form. Therefore, = Y (A, B, C) = AB + BC + CA = AB.

Explanation:

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Answer 2

Answer:

POS form of AB+AC+BC=Y(A,B,C)