position by time relation of a body of mass 2 kilogram is as X =2t+3t^2 . find the force acting on the body at t= 2 second
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x = 3t^2 + 2t
dx/dt = 6t + 2
v = 6t+2
dv/dt = 6
a = 6 m/s^2
So,
Force = mass * acceleration = 2(6) = 12 Newton
dx/dt = 6t + 2
v = 6t+2
dv/dt = 6
a = 6 m/s^2
So,
Force = mass * acceleration = 2(6) = 12 Newton
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