Position function of particle is given by s (t)=5ti+6t2j-10k.where t is in sec.find velocity and aceeleration of particle at t=1 sec.
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✓ s ( t ) = 5t î + 6t2 ĵ - 10 k̂
At t = 1 :
✓ v ( t ) = 5 î + 12t ĵ = 5 + 12( 1 ) = 17 ms⁻¹
✓ a ( t ) = 12ms⁻²
Cheers!
✓ s ( t ) = 5t î + 6t2 ĵ - 10 k̂
At t = 1 :
✓ v ( t ) = 5 î + 12t ĵ = 5 + 12( 1 ) = 17 ms⁻¹
✓ a ( t ) = 12ms⁻²
Cheers!
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