Position of a body changes according to equation x=t^2+2t-5. The average velocity of body in first three seconds is(x is in metre)
1) 4m/s
2) 5m/s
3) 20/3m/s
4) -20/3m/s
Answers
Answered by
4
answer : option (2) 5m/s
explanation : position of particle changes according to equation , x = t² + 2t - 5
it is clear that, position is function of time. so, instantaneous velocity is the differentiation of x with respect to time,
e.g., dx/dt = d(t² + 2t - 5)/dt
or, v = 2t + 2
now, average velocity during (t1 ≤ t ≤ t2) is given by, <v> =
here, t1 = 0, t2 = 3s and v = (2t + 2)
so, <v> =
=
= (3² + 6)/3
= 5 m/s
hence, average velocity = 5m/s
Answered by
1
Answer:
5m/s
Explanation:
3^2+2×3÷3
9+6÷3
15÷3
=5m/s
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