Question

Position of a body changes according to equation x=t2 +2t-5.The average velocity of body in first 3 seconds will be​

Answer 1

Hey Dear,

● Answer -

vavg = 5 units/s

◆ Explaination -

Equation for position of body is given as -

x = t² + 2t - 5

Differentiating w.r.t. time (t),

dx/dt = 2t + 2

At t = 0 s,

dx/dt = 2t + 2

u = 2 × 0 + 2

u = 2 units/s

At t = 3 s,

dx/dt = 2t + 2

v = 2 × 3 + 2

v = 8 units/s

Average velocity of the object is given by -

vavg = (u + v) / 2

vavg = (2 + 8) / 2

vavg = 5 units/s

Therefore, average velocity of the body in first 3 seconds is 5 units/s.

Thanks dear.