Question

Position of a body changes with time as x = (1 - 4)m, where tis in second. The average velocity of the body in first 2 s is
0-2 m/s
0 2 m/s
0-1 m/s
0 1 m/s​

Answer 1

Answer:

Given,

x=t

2

−4t+6

So, the change in velocity is:

dt

dx

=2t−4

Since velocity is changing,

At t=0,x

1

=6

At t=2,x

2

=2

So the magnitude of the distance traveled is:

6−2=4m

At t=3,x

3

=3

So distance traveled from t=2s to t=3s

x

3

−x

2

=3−2=1m

Thus the total distance is:

4+1=5m

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