Physics, asked by s81505209, 2 days ago

Position of a body changes with time as x=(t^2-4)m, where t is in second. The average velocity of the body is in first 2 s is​

Answers

Answered by mrneelgamer94
1

Answer:

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Explanation:

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Answered by estherbiju2004
0

Explanation:

x=t

2

−4t+6

So, the change in velocity is:

dt

dx

=2t−4

Since velocity is changing,

At t=0,x

1

=6

At t=2,x

2

=2

So the magnitude of the distance traveled is:

6−2=4m

At t=3,x

3

=3

So distance traveled from t=2s to t=3s

x

3

−x

2

=3−2=1m

Thus the total distance is:

4+1=5m

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