Question

position of a partical moving along x axis is given as x=2t³-4t²+6t+8 m find out initial velocity and also find its initial acceleration?

Answer 1

$initial \: velocity = 6 m/s\\ initial \: acceleration = - 4 m/s^2$. diffentiate the given instantaneous position to get instantaneous velocity and substitute t=0 to get initial velocity, now differentiate instantaneous velocity to get instantaneous acceleration substitute t=0 to get initial acceleration

Answer 2

Initial velocity 6
Initial acceleration -4