Question

Position of a particle as a function of time is given as x = 5t2 + 4 + 3. Find the acceleration of the particle at t=2 s?​

Answer 1

Answer:

The displacement is given as x=5t2+4t+3

⇒x−3=5t2+4t

assuming x−3=s,

s=4t+2110t2

comparing this with s=ut+21at2

we get u=4m/s and a=10m/s2

so velocity at t=2sec is v=u+at=4+10×2=24m/s.

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ANSWER BY KRITI ✌❤✌