Question

Position of a particle As a function of time is given as x(t)=12t^4 - 8t^2 . Find out instantaneous acceleration at t=2s

Answer 1

Answer:

hey dear....

$hëre's your answer$

To find acceleration at time t, we have to differentiate the position vector twice.

Differentiating the first time gives the velocity:

v(t) = r'(t) = 12t3i + 12tj

Differentiating a second time gives the accelaration:

a(t) = r''(t) = 36t2i + 12j

Plug in t=1 to solve for the final answer:

a(1) = r''(1) = 36i + 12j...

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Answer 2

Answer:

hey dear....

$hëre's your answer$

To find acceleration at time t, we have to differentiate the position vector twice.

Differentiating the first time gives the velocity:

v(t) = r'(t) = 12t3i + 12tj

Differentiating a second time gives the accelaration:

a(t) = r''(t) = 36t2i + 12j

Plug in t=1 to solve for the final answer:

a(1) = r''(1) = 36i + 12j...

[tex] follow me [/tex]..,.

mark my answer as brainlist ✅