Question

Position of a particle changes with time as x = 5t2 - 2t +1 where x is position in m and t is time in sec. Find the average speed of a particle between t=1s to t=4s.​

Answer 1

Answer: Average speed - 23m/s

Explanation:

x = 5t² - 2t + 1

position at time t₁ = 1s  is x₁ = (5 x 1 )- 2 + 1 = 4 m

Position at time t₂ = 4 s is x₂ = (5x16)-2 x 4 + 1 = 73 m

Average speed =  $\frac{(x2 - x1)}{(t2-t1)}$ = $\frac{(73-4)}{(4-1)}$  = 69/3 = 23 m/s