Question

position of a particle is given by x =3t^2 +bt what is its average acceleration between t =2 and t=5 second where b is a constant
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Answer 1

Answer:

a=6m/sec^2

Explanation:

x =3t^2+bt

v=6t+b

a=6=constant

Answer 2

Answer:

v=dx/dt

 =d(3t²+bt)/dt

 =6t+b

Average acceleration=Velocity/Time

                                   =v5-v2/5-2

                                   =6(5)+b-(6(2)+b)/3

                                   =30+b-12-b/3

                                   =18/3=6 m/s²