Question

position of a particle moving along x axis as x=2t2+3t+5 {x in mts , and t in sec},the rate of change of position of the particle at t=1 sec is

Answer 1

dx/dt = d(2t^2+3t+5)/dt
x= 4t+ 3
t=1
x= 4(1)+3
x=7

Answer 2

differente and put the time