Question

Position of a particle moving along x axis is given as x=-t^3+3t+4 then find average speed of particle for first 2seconds

Answer 1

Answer:

-10 m/s

Explanation:

here X is the distance covered by a particle along X axis,

therefore the average speed of particle for first two seconds is (dX/dt)at t=2 secs

=(d/dt)(-t^3+3t+4)

=(-3t^2+3)

=-3(2^2)+3

=-10m/s

here,negative sign indicates the opposite direction of the particle.