Question

position of a particle moving along x-axis is given by x= 2+8t-4t^2. The distance travelled by the particle from t=0 to t=2 is?

Answer 1

Answer:

9.333333units  (three occuring)

Explanation:

∫²(2+8t-4t²)=2t+4t²-4/3(t³)     definite integration

2(2)+4(2)²-4/3(2)³-[2(0)+4(0)²+4/3(0)³]    putting t=2 in integrated equation - t=0

4+16-8(4/3)

20-(32/3)=9.333333units  (three occuring)