Position of a particle moving along x-axis is given by x = 3t - 4t^2 + t^3, where x is in metre and t is in second. Find the average velocity of the particle in the time interval form t = 2 second to t = 4 second. (A) 7 m/s (B) 1 m/s (C) 13 m/s (D) 5 m/s
Answers
Answered by
0
Answer:
At t=1s, x=3(1)−4(1)
2
+(1)
3
=0
(b) At t=2s, x=3(2)−4(2)
2
+(2)
3
=−2
(c)At t=3s, x=3(3)−4(3)
2
+(3)
3
=0
(d)At t=4s, x=3(4)−4(4)
2
+(4)
3
=12
(e)Diplacement = 12m
(f)Total displacement between 2 to 4s = 14m
Total time = 2s
Average velocity = 14/2 = 7m/s
Similar questions