Position of a particle moving along x_axis is given by x=4+12t-6t find out the distance travelled by particle from t=0 to t=2sec
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x=4+12t+6t
at t=0s
x=4+12×0-6×0=4
and at t=2s
x=4+12×2-6×2=16
total=20u
at t=0s
x=4+12×0-6×0=4
and at t=2s
x=4+12×2-6×2=16
total=20u
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