Question

position of a particle moving along x-axis is given by x is equal to 2 + 8t - 4tt square the distance travelled by the particle from t=0 to t=2 second

is ​

Answer 1

the position is 8 along the axis

Answer 2

Answer:

The distance traveled by the particle is 4 m.

Explanation:

Given that,

The position of the particle is

$x=2+8t-4t^2$...(I)

The position of the particle at t = 0

Put the value of t in equation (I)

$x_{0}=2\ m$

The position of the particle at t = 2

Put the value of t in equation (I)

$x_{2}=2+8\times2-4\times2^2$

$x_{2}=2\ m$

We need to calculate the distance traveled by the particle from t = 0 to t = 2

The distance is

$d= x_{0}+x_{2}$

$d=2+2$

$d=4\ m$

Hence, The distance traveled by the particle is 4 m.