Position of a particle moving on a
straight line varies with time as
x=t^3/3 - 3t + 8t + 4
consider the motion of the particle from t = 0 to
t=5seconds , s1 is the total distance travelled and s2 is the distance travelled during retardation find s1/s2
Answers
Answered by
1
Answer:
Retardation till 3 sec
Explanation:
Position of a particle moving on a
straight line varies with time as
x=t^3/3 - 3t + 8t + 4
x = t³/3 - 3t² + 8t + 4
v = dx/dt = t² - 6t + 8
a = dv/dt = 2t - 6
2t - 6 < 0
=> t < 3
Retardation till 3 sec
Then acceleration
Answered by
0
Answer:
dhat
Explanation:
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