Question

Position of a particle varies with time
x = t^2 - 2t + 1, then magnitude of displacement of
the particle at t = 1 s to t = 2 s is (x is in meter
and t is in second)​

Answer 1

Answer:

1-2(1)+1

x=0

=(4)2-2(2)+1

=5

Answer 2

Answer:

Given equation of displacement (m) -

X = t² - 2t + 1

displacement at t = 1 s

=>X = t² - 2t + 1

=>X = 1² - 2 X 1 +1

=>X = 1 - 2 + 1

=>X = 0

hence at 1s it cover 0m.

displacement at t= 2s

=>X = t² - 2t +1

=>X = 2² - 2 X 2 +1

=>X = 4 - 4 +1

=>X = 1

hence at 2s it cover 1m.