Physics, asked by likhithsaibandari, 1 month ago

position of an object is defined by s(t) =
t^3 - 12t^2+ 36t where t is in seconds, and
s is in metres.
a)when the object is speeding up.
b) when the object is slowing down

Answers

Answered by piyushraj54
0

Answer:

Explanation:

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