Question

position of an object y=4a+5t cube what is the velocity at t =0 and t=2s​

Answer 1

Answer:

velocity = 0m/s at t = 0 , and

velocity = 60m/s at t = 2s

Explanation:

y = 4a+5t³

we know that, v = dy/dt

v = d/dt (4a+5t³) = 15t²

v = 0 m/s at t = 0 and

v = 15(2)² = 60m/s at t = 2s.