Question

Position of particle at any constant is x=2t²-t³ find velocity and acceleration at any instant

Answer 1

Answer:

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Answer 2

Answer:

velocity = 4t - 3t² m/s,acceleration = 4- 6tm/s²

Explanation:

v = dx/dt

v = 2(2 t²/t) - 3t³/t

v = 4t - 3t²

a = dv/dt

a = 4dt/dt - 2(3 t²/2)m/s²

a = 4 - 6t m/s²