Position of particle is given by X=3t-9. Find the time when particle crosses the origin.
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Answer. THEREFORE, t = 3 seconds.The position of a particle moving along x-axis is given by
x=(−2t3+3t2+5)m
Velocity, v=dtdx=0
−6t2+6t=0. . . . . . .(1)
6t(−t+1)=0
−t+1=0
t=1sec
Acceleration, a=dtdv
a=−12t+6
a∣t=1sec=−12×1+6
a∣t=1sec=−6m/s2
The correct option is C.
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