Question

Position of particle is given by x is equals to t^2-4t + 5 where x is in metre and t is in second find position of particle when velocity is zero​

Answer 1

Explanation:

The displacement is given as x=5t

2

+4t+3

⇒x−3=5t

2

+4t

assuming x−3=s,

s=4t+

2

1

10t

2

comparing this with s=ut+

2

1

at

2

we get u=4m/s and a=10m/s

2

so velocity at t=2sec is v=u+at=4+10×2=24m/s