Question

Position(S)=2t³-3t²+2. Velocity at the end of 2second.
Q)what is the difference??

v= 6/2 and v= d(2t³-3t²+2)/dt,when t=2

Why we get different answer from calculas method and by the formula of velocity.

Please explain me........

Answer 1

Answer:

Explanation:

We express the position of an object as a function of time,

$f( t ) = 2t^3 - 3t^2 + 2$

Now, velocity is,

$v = \frac{d}{dt} f( t )$

We calculate this derivative.

$v = \frac{d}{dt} f( t ) = 6t^2 - 6t$

For t = 2 seconds,

$v = 6(2)^2 - 6(2) = 24 - 12 = 12 \ s$

I think you have calculated the derivative incorrectly. Try checking it once again. The velocity will remain the same