position time graph for an object moving with uniform negative acceleration
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Hi, i got it from my Ncert text!
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Answer:
it will be parabolic by nature, more specifically a downward opening parabola.
Explanation:
from equation s=ut-1/2at^2, we can see the s is directly proportional to t^2. From that we can conclude that a graph plotted between x(s) position and time t will be parabolic by nature.
Trace the curve by putting different values of u and t.
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