Question

Position time relation using trapezium

Answer 1

Answer:

Explanation:

Equation for position velocity relation

 consider graph given  in figure .

 We know that distance travelled s by a body in time t is given by the area under line AB which is area of trapezium OABC.

So we have

Distance travelled=s= Area of Trapezium OABC

S=(sum of parallel sides) x height/2

=(OA+CB)x OC/2

since OA+CB=u+v and OC=t,

Then we gt

s=(u+v)t/2get,-Equation for position velocity relation

 consider graph given  in figure .

 We know that distance travelled s by a body in time t is given by the area under line AB which is area of trapezium OABC.

So we have

Distance travelled=s= Area of Trapezium OABC

S=(sum of parallel sides) x height/2

=(OA+CB)x OC/2

since OA+CB=u+v and OC=t,

Then we gt

s=(u+v)t/2get-Equation for position velocity relation

 consider graph given  in figure .

 We know that distance travelled s by a body in time t is given by the area under line AB which is area of trapezium OABC.

So we have

Distance travelled=s= Area of Trapezium OABC

S=(sum of parallel sides) x height/2

=(OA+CB)x OC/2

since OA+CB=u+v and OC=t,

Then we gt

s=(u+v)t/2get,---------(1)

Equation for position velocity relation

 consider graph given  in figure .

 We know that distance travelled s by a body in time t is given by the area under line AB which is area of trapezium OABC.

So we have

Distance travelled=s= Area of Trapezium OABC

S=(sum of parallel sides) x height/2

=(OA+CB)x OC/2

since OA+CB=u+v and OC=t,

Then we gt

s=(u+v)t/2get,---------(1)

from, velocity time relation,

t=v-u/a

substituting the value of 't' in equation 1

we get,

s=(u+v)/2(v-u)/2

or we have

v²=u²+2as

which is equation for position velocity relation.