Position-time relationship of a particle executing simple harmonic motion is given by equation x=2sin(50pit+(2pi)/(3)) where x is in meters and time t is in seconds. What is the position of particle at t=1s ?
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Explanation:
at time t = 1sec x=2sin(50pi(1)+(2pi)/(3)) = 2 sin2π/3 that is √3 and u can solve for time period from 2π/w
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