Question

position vector i+3j+4k in the plane r.(2i-j+k)+3=0

Answer 1

so equation of plan will be 2x-3y+z +3 =0
now let a point on position vector be a(i+3j+4k)
2a -3a + 4a +3 =0
so a=(-1)
so point is
-(I+3j+4k)