Question

Position vector of a moving particle is given by r = [(î -j )t (1-5)] m. Calculate the velocity of the particle at t=1s.​

Answer 1

Answer:

Explanation:

15m/s

correct answer is A.

a=2(t−1)

=2t−2

dt

dv

​

=2t−2

dv=(2t−2)dt

integrating both side we get,

∫dv=∫(2t−2)dt

v=t  

2

−2t+c

=(5)  

2

−2×5

=25−10

=15m/s