Physics, asked by JTofa, 6 months ago

Position x of a moving particle with time t is given by x = 6 {t-e^(-2t}. Initial and final velocity of the particle will be respectively
(1) 6 m/s and 12 m/s
(2) 6 m/s and 18 m/s
(3) 18 m/s and 12 m/s
(4) 18 m/s and 6 m/s​

Answers

Answered by swayamprabhanayaksp
4

Answer:

answer ok please follow me

Attachments:
Similar questions