Position x of a particle varies with time t as x=a×t square ,where a & b are constant . What is the velocity of the particle at t= 1s ?
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Answer:
2a
Explanation:
Differentiating w.r.t. x, we get,
dx/dt= 2at
•°• v= 2at , at t=1s
v=2a(1)
=2a
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