Question

Positive charge Q is distributed uniformly over a circular ring of radius R. A particle having a mass m and a negative charge q, is placed on its axis at a distance x from the centre. Find the force on the particle. Assuming x ltltR, find the time period of oscillation of the particle if it is released from there.

Answer 1

Answer:

here is your answer hope it's helpfull..

Answer 2

Explanation:

We know: Electric field 'E' at 'P' due to teh charged ring

=

(R

2

+x

2

)

3/2

KQx

=

R

3

KQx

Force experienced

′

F

′

=Q×E=

R

3

q×K×Qx

Now, amplitude=x

So, T=2π

KQqx/mR

3

x

=2π

KQqx

mR

3

x

=2π

Qq

4πε

0

mR

3

=

qQ

4π

2

×4πε

0

mR

3

⇒T=[

qQ

16π

3

ε

0

mR

3

]

1/2

.