Physics, asked by anurag665435, 9 months ago

positive charges of 2 microC and 8 microC are placed 15 cm apart. at what distance from the smaller charge the electric field due to them will be zero​

Answers

Answered by subbuorg
2

Answer:

HI

Explanation:

The electric field will be zero at a point where the forces exerted by charges 4q and q on a test charge q  

0

​  

 are equal and opposite. Let this point be at a distance x from 4q, then its distance from q=30−x. If F  

1

​  

 is force due to 4q and F  

2

​  

 due to q, then F  

1

​  

=F  

2

​  

,

i.e.,  

4πϵ  

0

​  

 

1

​  

 

x  

2

 

4q×q  

0

​  

 

​  

=  

4πϵ  

0

​  

 

1

​  

 

(30−x)  

2

 

q×q  

0

​  

 

​  

 

(or)  

x  

2

 

4

​  

=  

(30−x)  

2

 

1

​  

 

⇒2(30−x)=x

(or) x=20cm.

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