positive charges of 2 microC and 8 microC are placed 15 cm apart. at what distance from the smaller charge the electric field due to them will be zero
Answers
Answered by
2
Answer:
HI
Explanation:
The electric field will be zero at a point where the forces exerted by charges 4q and q on a test charge q
0
are equal and opposite. Let this point be at a distance x from 4q, then its distance from q=30−x. If F
1
is force due to 4q and F
2
due to q, then F
1
=F
2
,
i.e.,
4πϵ
0
1
x
2
4q×q
0
=
4πϵ
0
1
(30−x)
2
q×q
0
(or)
x
2
4
=
(30−x)
2
1
⇒2(30−x)=x
(or) x=20cm.
Similar questions