positive real root of 3−−11=0
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To Find : a root by bisection method. Solution: x³ - x - 11 = 0. f(0) = - 11. f(1) = - 11. f(2) = -5. f(3) = 13. one root lies between 2 & 3. (2 +3 )/2 = 2.5.
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