Positive sqare root of 3+√5
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Step-by-step explanation:
I assume that you want the square roots, not cube roots, fourth roots ….
So, we want to find y given that:
y2=3+5–√=2+1+5–√=2+21+5√2
Now, 1+5√2 is a well-known mathematical value; it is called the golden ratio and designated using ϕ , so:
y2=2+2ϕ=2(1+ϕ)
One of ϕ′s properties is that 1+ϕ=ϕ2 , so:
y2=2ϕ2⇒y=±2–√ϕ
=±2√+10√2
≈±2.288245611
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