Math, asked by ROYALCHALLENGE, 1 year ago

positive square root value of root 32 minus root 24

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Answered by Thinker422
4
value is 56-32 root 3
Answered by Alcaa
3

\sqrt{32} -\sqrt{24}  =  4 \sqrt{2} - 2\sqrt{6}  = 0.74.

Step-by-step explanation:

We have to find the positive square root value of root 32 minus root 24.

The given expression is: \sqrt{32} -\sqrt{24}

The factorization of number 32 is;

32 = 2 \times 16

16 = 2 \times 8

8 = 2 \times 4

4 = 2 \times 2

2 = 2 \times 1

So, the prime factorization of 32 = 2 \times 2 \times 2 \times 2 \times 2.

Similarly, the factorization of number 24 is;

24 = 2 \times 12

12 = 2 \times 6

6 = 2 \times 3

3 = 3 \times 1

So, the prime factorization of 24 = 2 \times 2 \times 2 \times 3.

Putting these factorizations inside the root we get;

\sqrt{32} -\sqrt{24}  =  \sqrt{2 \times 2 \times 2 \times 2 \times 2  } -\sqrt{2 \times 2 \times 2 \times 3}

                  =  (2 \times 2) \sqrt{2}  - 2 \sqrt{2 \times 3}

                  =  4 \sqrt{2} - 2\sqrt{6}

                  =  2(2\sqrt{2} -\sqrt{6} )

As we know that : \sqrt{2} = 1.41  and  \sqrt{6} = 2.45    {rounding to 2 decimal points}

So, \sqrt{32} -\sqrt{24}  =  2 \times (2 \times 1.41 - 2.45)

                         =  2 \times 0.37 = 0.74

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