Math, asked by sailajasrinivas, 11 months ago

Post all algebraic identies please

Answers

Answered by vishalmaurya2812
1

Step-by-step explanation:

Identity I: (a + b)2 = a2 + 2ab + b2

Identity II: (a – b)2 = a2 – 2ab + b2

Identity III: a2 – b2= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x2 + (a + b) x + ab

Identity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

Identity VI: (a + b)3 = a3 + b3 + 3ab (a + b)

Identity VII: (a – b)3 = a3 – b3 – 3ab (a – b)

Identity VIII: a3 + b3 + c3 – 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca)

Answered by Agamsain
5

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What ars Algebraic Identities ?

"The algebraic equations which are valid for all values of variables in them are called algebraic identities."

  • They are also used for the factorization of polynomials.
  • In this way, algebraic identities are used in the computation of algebraic expressions and solving different polynomials.

Some Basic Algebraic Identities-

  • (a + b)² = a² + 2ab + b²
  • (a − b)² = a² − 2ab + b²
  • (a + b) (a – b) = a² – b²
  • (x + a) (x + b) = x² + (a + b)x + ab
  • (x + a) (x – b) = x² + (a – b)x – ab
  • (x – a) (x + b) = x² + (b – a)x – ab
  • (x – a) (x – b) = x² – (a + b)x + ab
  • (a + b)³ = a³ + b³ + 3ab (a + b)
  • (a – b)³ = a³ – b³ – 3ab (a – b)

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