Potassium Bromide(aq)+ Barium Iodide(aq) ---> Potassium Iodide(aq) + Barium Bromide(s)
Write the Balanced Chemical Equation and also Identify the type of reaction.
Answers
Given word equation:
Potassium Bromide(aq)+ Barium Iodide(aq) ---> Potassium Iodide(aq) + Barium Bromide(s)
Its symbolic skeletal equation will be:
KBr + BaI₂ ---> KI + BaBr₂
Here,
LHS RHS
K - 1 K - 1
Br - 1 Br - 2
Ba - 1 Ba - 1
I - 2 I - 1
If we make Br on LHS 2, we have
2KBr + BaI₂ ---> KI + BaBr₂
LHS RHS
K - 2 K - 1
Br - 2 Br - 2
Ba - 1 Ba - 1
I - 2 I - 1
If we make K on RHS 2, we have
2KBr + BaI₂ ---> 2KI + BaBr₂
LHS RHS
K - 2 K - 2
Br - 2 Br - 2
Ba - 1 Ba - 1
I - 2 I - 2
The bold one the the balance equation as in it, the no. of atoms and molecules on both sides of the ---> are equal.
It is a displacement reaction.
answer is 2kBr + Bal2 —> 2Kl + BaBr2 the type of reaction is double displacement reaction