potassium Bromide + barium iodide = to potassium iodide + barium Bromide
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Answer:
2KBr2(aq) + BaI2(aq) => 2KI (aq) + BaBr2(aq)
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Explanation:
(a) Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s)
2KBr (aq) +BaI2(aq) →2KI (aq)+BaBr 2(s)
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