Chemistry, asked by Alanhunter, 9 months ago

Potassium chlorate (KCIO4) is made in the following sequence of reactions:
Cl2(g) + KOH(cold & diluted) —>KCI+KCIO+H2O
KCIO -> KCl + KCIO3
KCIO3 →KCIO4 +KCI
What mass of Cl2 is needed to produce 1.385 kg of KCIO4?
For the above set of reactions what will be amount of KCl produced when 142 g of Cl2 is taken?​

Answers

Answered by ashmitpandey88
2

Answer:

The arrangement of conditions includes;

Cl  

2

​  

+2KOH→KCl+KClO+H  

2

​  

O......(1)

3KClO→2KCl+KClO  

3

​  

......(2)

4KClO  

3

​  

→3KClO  

4

​  

+KCl.......(3)

From the eqn(3)

The proportion    

KCl

KClO  

4

​  

 

​  

=  

1

3

​  

 

Implying that we have 3 moles of KClO  

3

​  

 

We have 1mole of KCl

Since the molar mass of KClO  

4

​  

 is 138.55,

We have =  

138.55

156

​  

 

Moles delivered =1.126moles

On the off chance that we accept 100% yield these originated from (1.125×  

3

4

​  

) moles of KClO  

3

​  

 

=1.501 moles of KClO  

3

​  

 required to deliver 156g of KClO  

4

​  

 

Moles of KClO expected to deliver 1.501 moles of KClO  

3

​  

 

=1.501×3=4.504 moles of KClO from eqn(2)

From eqn(1)

Moles of Cl2=moles of KClO =4.504 moles.

Along these lines, the mass of Cl  

2

​  

=4.504×71

Mass of Cl  

2

​  

=319g to deliver 156g of KClO  

4

​  

 if 100% yield is accepted in the three compound responses.

Hence, this is the answer.

Explanation:

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